Question

${216}^{\frac{1}{3}}\times {26}^4\times {39}^4÷[{12}^4\times 3\times 2^{-36}]={13}^{?}$

• A. 8
• B. 12
• C. 4
• D. 10
• E. 16

Answer 1

The correct option is A 8

Here,
$\frac{(216{)}^{\frac{1}{3}}\times {26}^4\times (39{)}^4}{\left({12}^4\right)\times 3\times 2^{-3}}={13}^x\Rightarrow \frac{6\times 2^4\times 3^4\times {13}^8}{(2\times 6{)}^4\times 3\times 2^{-3}}={13}^x\Rightarrow \frac{6\times 6^4\times {13}^8}{6\times 6^4}={13}^x\Rightarrow {13}^8={13}^x\Rightarrow x=8$