Question

22. If the distance of Uranus from Sun is 2870000000 km, then the distance in scientific notation is written as
$$\begin{gathered} 1.2.87\times {10}^{12}cm \\ 2.2.87\times {10}^{14}cm \\ 3.2.87\times {10}^{11}cm \\ 4.2.87\times {10}^{15}cm \end{gathered}$$

Answer 1

$$\begin{gathered} \mathrm{Hi}, \\ \mathrm{Distance}\mathrm{of}\mathrm{uranus}\mathrm{from}\mathrm{sun} \\ =2870000000\mathrm{km} \\ =287\times 10000000 \\ =287\times {10}^7 \\ =2.87\times 100\times {10}^7 \\ =2.87\times {10}^2\times {10}^7\left[\mathrm{since}{\mathrm{a}}^{\mathrm{m}}\times {\mathrm{a}}^{\mathrm{n}}={\mathrm{a}}^{\mathrm{m}+\mathrm{n}}\right] \\ =2.87\times {10}^9\mathrm{km} \\ =2.87\times {10}^9\times 1000\mathrm{m} \\ =2.87\times {10}^9\times 1000\times 100\mathrm{cm} \\ =2.87\times {10}^9\times {10}^3\times {10}^2=2.87\times {10}^{14}\mathrm{cm} \\ \mathrm{Regards} \end{gathered}$$