2230 BCE and 2230 BC refer to the same year.

True

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False

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Solution

The correct option is A True

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Similar questions

$3 c o s^{2} 60^{o} + 2 c o t^{2} 30^{o} - 5 s i n^{2} 45^{o}$ = ?

(a) $\frac{13}{6}$ (a) $\frac{17}{4}$ (c) 1 (d) 4

\frac{13}{6}

\frac{17}{4}

3 {cosec}^{2} 60^{\circ} - 2 {cot}^{2} 30^{\circ} + {sec}^{2} 45^{\circ}

\frac{17}{4}

\frac{13}{6}

Prove that $3 t a n^{2} 45^{\circ} - s i n^{2} 60^{\circ} - (\frac{1}{2}) c o t^{2} 30^{\circ} + (\frac{1}{8}) s e c^{2} 45^{\circ}$ = 1

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