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Q.23. One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

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Solution

Dear Student,

$L e t t h e t w o d i g i t n u m b e r b e 10 x + y w h e r e x i s 10 t h p l a c e a n d y i s u n i t p l a c e A l s o g i v e n t h a t o n e o f t h e d i g i t s i s t h r e e t i m e s t h e o t h e r s o x = 3 y o r y = 3 x i f w e i n t e r c h a n g e t h e d i g i t s o f t h e n u m b e r a n d a d d t h e t w o n u m b e r s 10 x + y + 10 y + x = 88 11 (x + y) = 88 x + y = 8 p o s s i b l e v a l u e s a r e (1, 7) (2, 6), (3, 5) (4, 4) (5, 3) (6, 2) (7, 1) o n l y (2, 6) a n d (6, 2) s a t i s f i e s t h e t h e c o n d i t i o n x = 3 y o r y = 3 x H e n c e p o s s i b l e 2 d i g i t n u m b e r = 26 o r 62$

Regards,

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One of the two digits of a two digit number is three times the other digit . If you interchange the digits of this two digit number and add the resulting number to the original number you get $88$ .What is the original number ?

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23 give fast Q.23. One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?

23 give fast
Q.23. One of the two digits of a two digit number is three times the other digit. If you interchange the digits of this two-digit number and add the resulting number to the original number, you get 88. What is the original number?