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Standard XII

Chemistry

Entropy

25 g of Ca ...

Question

25 g of $C a {C O}_{3}$ completely reacts with $H_{2} {S O}_{4}$ and gives 8 g of ${C O}_{2}$ then calculate the percentage purity of $C a {C O}_{3}$ .
$C a {C O}_{3} + H_{2} {S O}_{4} ⟶ C a {S O}_{4} + {C O}_{2} + H_{2} O$

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Solution

Solution:-
Molecular weight of $C a C O_{3} = 100 g$
Molecular weight of $C O_{2} = 44 g$
Decomposition of $C a C O_{3}$ -
$C a C O_{3} ⟶ C a O + C O_{2}$
Now, from the above reaction-
Weight of pure $C a C O_{3}$ required to produce $44 g$ of $C O_{2} = 100 g$
Weight of pure $C a C O_{3}$ required to produce $8 g$ of $C O_{2} = \frac{100}{44} \times 8 \approx 18.18 g$
Given weight of $C a C O_{3} = 25 g$
Now,
Amount of pure $C a C O_{3}$ in $25 g$ of given $M g C O_{3} = 18.18 g$
Thus,
Amount of pure $C a C O_{3}$ in $100 g$ of given $M g C O_{3} = \frac{18.18}{25} \times 100 = 72.72 g$
Therefore,
The percentage purity of given $C a C O_{3} = 72.72 %$

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Similar questions

Calcium carbonate reacts with aqueous $HCl$ to give ${CaCl}_{2}$ and ${CO}_{2}$ according to the reaction given below

$\underset{Calcium Carbonate}{{CaCO}_{3} (s)} + \underset{Hydrochloric acid}{2 HCl (aq)} ⟶ \underset{Calcium Chloride}{{CaCl}_{2} (aq)} + \underset{Carbon dioxide}{{CO}_{2} (g)} + \underset{Water}{H_{2} O (l)}$

What mass of ${CaCO}_{3}$ is required to react completely with 25 mL of 0.75 M HCl?

1) 0.6844

2) 0.9375

3) 0.4265

4) 0.2785

Q. 56.75 g of

H C l

is dissolved in 2 L of water. Calculate the mass of

C a C O_{3}

required to react completely with 25 mL of this

H C l

solution.

C a C O_{3} + 2 H C l \to C a C l_{2} + C O_{2} + H_{2} O

Q. 4 g of an impure sample of

C a C O_{3}

on treatment with excess HCI produce 0.88 g

C O_{2}

. What is the per cent purity of

C a C O_{3}

sample ?

Q. Calculate the amount of

C a C O_{3}

in grams having percentage purity

25 %

that produces

0.56

litre of

C O_{2}

at STP on heating?

Q. Which of the following statements is/are correct?

1.0

g mixture of

C a C O_{3} (s)

and glass beads liberate

0.22

g of

C O_{2}

upon treatment with excess of

H C l

. Glass does not react with

H C l

C a C O_{3} + 2 H C l \to C O_{2} + H_{2} O + C a C l_{2}

[Molecular weight of

C a C O_{3} = 100

g/mol,

C O_{2} = 44

g/mol and atomic weight of

C a = 40

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25 g of CaCO3 completely reacts with H2SO4 and gives 8 g of CO2 then calculate the percentage purity of CaCO3.CaCO3+H2SO4⟶CaSO4+CO2+H2O

25 g of $C a {C O}_{3}$ completely reacts with $H_{2} {S O}_{4}$ and gives 8 g of ${C O}_{2}$ then calculate the percentage purity of $C a {C O}_{3}$ .
$C a {C O}_{3} + H_{2} {S O}_{4} ⟶ C a {S O}_{4} + {C O}_{2} + H_{2} O$