25 mL of 3.0 M HNO3 is mixed with 75 mL of 4.0 M HNO3. If the volumes are additive, and 10 mL of this mixture is titrated against 2.5 M NaOH, find the volume of NaOH needed for complete neutralisation?
A
15 mL
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B
20 mL
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C
25 mL
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D
30 mL
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Solution
The correct option is A 15 mL Dilution: M1V1+M2V2=MfVf 3.0×25+4.0×75=Mf×100 Mf(HNO3)=3.75M For neutralization: HNO3+NaOH→NaNO3+H2O (M×V×nf)HNO3=(M×V×nf)NaOH nf is 1 for HNO3 nf is 1 for NaOH 3.75×10=2.5×VNaOH VNaOH=15mL