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Question

25 mL of 3.0 M HNO3 is mixed with 75 mL of 4.0 M HNO3. If the volumes are additive, and 10 mL of this mixture is titrated against 2.5 M NaOH, find the volume of NaOH needed for complete neutralisation?

A
15 mL
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B
20 mL
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C
25 mL
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D
30 mL
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Solution

The correct option is A 15 mL
Dilution:
M1V1+M2V2=MfVf
3.0×25+4.0×75=Mf×100
Mf(HNO3)=3.75 M
For neutralization:
HNO3+NaOHNaNO3+H2O
(M×V×nf)HNO3=(M×V×nf)NaOH
nf is 1 for HNO3
nf is 1 for NaOH
3.75×10=2.5×VNaOH
VNaOH=15 mL

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