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Question

25 mL of a solution containing HCl was treated with excess of KIO3 and KI solution of unknown concentration, where I2 liberated is titrated against a standard solution of 0.021 M Na2S2O3 solution, whose 24 mL were used up. The strength of HCl is :

A
0.0165
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B
0.0201
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C
0.0868
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D
none of the above
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Solution

The correct option is B 0.0201
I2+2Na2S2O32NaI+Na2S4O6

KIO3+5KI+6HCl6KCl+3H2O+3I2
6 mole HCl=3 mole I2=6 mole Na2S2O3
1 mole HCl=1 mole Na2S2O3
25×M=24×0.021
M=0.020M
Hence, the strength of HCl is 0.020 M.

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