CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A mixture containing 0.05 mole of K2Cr2O7 and 0.02 mole of KMnO4 was treated with excess of KI in acidic medium. The liberated iodine required 1.0 L of Na2S2O3 solution for titration. Concentration of Na2S2O3 solution was ?

A
0.40 mol L1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.20 mol L1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.25 mol L1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.30 mol L1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.40 mol L1
eq. wt. of K2Cr2O7=Molar mass6

eq. wt. of KMnO4=Molar mass5

eq. of Na2S2O3 = eq. of I2 liberated
= eq. of KMnO4 + eq. of K2Cr2O7
or N×1=0.02×5+0.05×6

N=0.4 or M=0.4

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Concentration of Solutions
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon