25 mL of water is added to 100 mL of a decinormal $H C l$ solution. Calculate the normality of the resultant mixture.

0.08 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.60 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.15 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.03 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0.08 N
$N_{1} V_{1} = N_{2} V_{2}$
$\Rightarrow (0.1 \times 100) = (N \times 125)$
Normality of the mixture = 0.08 N

Suggest Corrections

Similar questions

H C l

25ml of 3.0N HCl and 75ml of 0.05N HCl when mixed together, the normality of the resulting solution is

H C l

50 {cm}^{3}

0.5 N H C l

Join BYJU'S Learning Program