Question

$25\text{mL}$ of a solution of barium hydroxide on titration with a $0.1\text{M}$ solution of $HCl$ gave a titre value of $35\text{mL}$. The molarity of the barium hydroxide solution is:

• A. $0.07\text{M}$
• B. $0.14\text{M}$
• C. $0.28\text{M}$
• D. $0.35\text{M}$

Answer 1

The correct option is A $0.07\text{M}$

Let the molarity of $Ba(OH{)}_2$ solution be $k\text{M}$
$\text{n-factor}\times M_1{V}_1=\text{n-factor}\times M_2{V}_2$
$2\times k\times 25=1\times 0.1\times 35$ (Since n-factor of $Ba(OH{)}_2=2$ and of $HCl=1$)
Molarity of $Ba(OH{)}_2$ solution $=0.07\text{M}$