Question

250 mL of an aqueous solution of 6.3 g of oxalic acid dihydrate is diluted to 2 L. The normality of the resultant solution is:

• A. 0.07 N
• B. 0.05 N
• C. 0.50 N
• D. 0.04 N

Answer 1

The correct option is B 0.05 N

n-factor for oxalic acid dihydrate = 2
$\text{Normality}=\frac{\text{number of gram equivalents}}{\text{total volume of solution in mL}}=\frac{6.3\times 2\times 1000}{126\times 250}=0.4N$

Now, the solution is diluted to 2L.
$N_1{V}_1=N_2{V}_2\Rightarrow (0.4\times 250)=(N\times 2000)$
Normality of the final solution = 0.05 N