Question

An aqueous solution of 6.3 g oxalic acid dihydrate is made up to 250 mL. The volume of 0.1 N NaOH required to completely neutralise 10 mL of this solution is

• A. 40 mL
• B. 20 mL
• C. 10 mL
• D. 4 mL

Answer 1

The correct option is A 40 mL

The normality of oxalic acid dihydrate is
$\frac{6.3}{63}\times \frac{1}{250}\times 1000=0.4$
[Ew for $(COOH{)}_2.2H_{2}O$ is 63]
$N_1{V}_1\left(acid\right)=N_2{V}_2\left(base\right)$
or $0.4\times 10=0.1\times V_2$
or $V_2$ = 40 mL