Question

An aqueous solution of 6.3 g of oxalic acid dihydrate is made upto 250 ml. The volume (in ml) of 0.1 N NaOH required to completely neutralize 10 ml of this solution is:

Answer 1

$\text{Normality of oxalic acid}=\frac{6.3\times 1000}{63\times 250}=0.4\text{N}$
$N_1{V}_1=N_2{V}_2$
$10\times 0.4=0.1\times V$
$\Rightarrow V=\frac{10\times 0.4}{0.1}=40\text{ml}$