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# 250 gm of water and equal volume of alcohol of mass 200 gm are replaced successively in the same calorimeter which cools from 60∘C to 55∘C in 130 seconds and 67 seconds respectively. If the water equivalent of the calorimeter is 10 gm, then the specific heat of alcohol (in cal/g ∘C) is (Assume that rate of heat loss in both the cases remains same)

A
1.30
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B
0.67
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C
0.62
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D
0.985
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Solution

## The correct option is C 0.62Mass of alcohol =200 gm When water is added to calorimeter, Given water equivalent of calorimeter, W=10 gm Fall of temperature =60−55=5∘C Time taken by water to cool =130 sec. Heat lost by water and calorimeter =(250+10)(1)5=260×5=1300 cal Rate of loss of heat =10calsec When alcohol is added, Heat lost by alcohol and calorimeter is =(200s+10)5 cal Heat lost by alcohol and calorimeter is =(200s+10)567calsec Rates of loss of heat in the two cases are equal ∴(200s+10)567=10 1000s+50=670 1000s=620 s=0.62calg∘C Hence, the correct answer is option (c).

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