Question

$252$ gm. of oxalic acid with molecular formula $C_2{H}_2{O}_4\cdot 2H_{2}O$ dissolve in water to form $250$ ml. of the solution. It's normality will be:

• A. 16 N
• B. 8 N
• C. 32 N
• D. 4 N

Answer 1

The correct option is A 16 N

Molecular weight of oxalic acid= $126g$

Equivalent weight of oxalic acid= $\frac{126}{2}=63$

Given, $252g$ is dissolved in $250ml$

$\therefore$ Normality= $\frac{Weight/Eq.Weight}{Volume/1000}$

$=\frac{252\times 1000}{63\times 250}=16N$