Question

$26$ cc of $C{O}_2$ are passed over red hot coke. The volume of $CO$ evolved is:

• A. $15$ cc
• B. $10$ cc
• C. $32$ cc
• D. $52$ cc

Answer 1

Answer: (D)

$52$ cc

$26{cm}^3$ of ${CO}_2$ is passed over red-hot coke.

The reaction will be:

${CO}_2+C⟶2CO$

$1$ mol of ${CO}_2$gives $2$ moles of CO.

At STP, $1$ mol = $22.4L$

$22.4Lof{CO}_2⟶2\times 22.4LofCO1Lof{CO}_2⟶2\times \frac{22.4}{22.4}LofCO$

Volume of ${CO}_2$ given = $26{cm}^3$

$26\times {10}^{-3}Lof{CO}_2⟶26\times {10}^{-3}\times 2\times \frac{22.4}{22.4}LofCO⟶52\times {10}^{-3}LofCO⟶52{cm}^{3}ofCO$

Hence, option $D$ is correct.