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Volume of Gases and Number of Moles

26 cm3 of C...

Question

$26 c m^{3}$ of ${C O}_{2}$ are passed over red hot coke. The volume of $C O$ evolved is:
$C_{(s)} + {C O}_{2 (g)} \to {2 C O}_{(g)}$

15 c m^{3}

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10 c m^{3}

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32 c m^{3}

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none of these

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Solution

The correct option is D none of these
$C_{(5)} + {C O_{2}}_{(g)} ⟶ 2 {C O}_{(g)}$
$26 c m^{3}$
$1$ volume of $C O_{2}$ gives $2$ volumes of $C O$
Therefore, $26 c m^{3}$ of $C O_{2}$ will give $52 c m^{3} o f C O$ .

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