Question

$({27}^{-2}{)}^{1/3}\times \sqrt{4^3}=$___

• A. 7/9
• B. 8/9
• C. 9/9
• D. 10/9

Answer 1

The correct option is B 8/9

$\left(\right(27{)}^{-2}{)}^{1/3}\times \sqrt{43}$

$\Rightarrow 3\left(\frac{3\times -2}{3}\right)\times (2^2{)}^{\frac{3\times 2}{2}}$

$\Rightarrow \frac{2^3}{3^2}=\frac{8}{9}$