Question

. 27. A student was performing experiments with the following specifications. )
A circuit with one bulb and one cell connected in series. ) A circuit with two bulbs and two cells connected in series. A circuit with three bulbs and two cells connected in series.
d) A circuit with two bulbs and three cells connected in series.
i) Which of these circuits has the smallest amount of current flowing? Give reason.
ii) Which of these circuits have the same amount of current flowing? Give reason

Answer 1

Dear Student

By ohm's law
I =V/R

For (a)
I = V/R

For (b)
I =2V/2R =V/R

For (c)
I= 2V/3R

For(d)
I =3V/2R

So
(i) Circuit c has the smallest amount of current flowing
(ii) Circuit (a) and (b) have the same amount of current flowing.

Regards
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