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Byju's Answer
Standard XII
Physics
Gas laws from KTG
273 ml of a g...
Question
273
m
l
of a gas at STP was taken to
27
o
C
and
600
m
m
pressure. The final volume of the gas would be:
A
273 mL
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B
300 mL
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C
380 mL
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D
586 mL
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Solution
The correct option is
C
380 mL
We know that, for constant no. of moles of gas,
P
1
V
1
T
1
=
P
2
V
2
T
2
Given,
initial conditions,
P
1
=
760
m
m
(STP)
V
1
=
273
m
L
T
1
=
273
K
(STP)
Final conditions,
P
=
600
m
m
T
=
300
K
Thus,
V
2
=
P
1
V
1
T
1
×
T
2
P
2
=
760
×
273
×
300
273
×
600
=
380
m
L
Hence, option C is correct.
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