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Standard XII
Physics
Idea behind a PPC
28 0.2F capac...
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28 0.2F capacitor is charge to 600V by a battery,on removing the battery,it is connected with another parallel plate condenser of 1F.The potential decreases to
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Q.
A parallel-plate condenser of capacitance
C
is connected to a battery and is charged to potential
v
. Another condenser of capacity
2
C
is connected to another battery and is charged to potential
2
V
. The charging batteries are removed and now the condensers are connected in parallel in such a way that the positive plate of one is connected to the negative plate of another. The final energy of this system is
Q.
A parallel plate condenser of capacity C is connected to a battery and is charged to potential V. Another condenser of capacity
2
C is connected to another battery and is charged to potential
2
V. The charging batteries are removed and now the condensers are connected in such a way that the positive plate of one is connected to negative plate of another. The final energy of this system is :
Q.
A capacitor
0.2
μ
F
is charged to
600
V
.
After removing the battery, it is connected to
1
μ
F
capacitor in parallel. The voltage across
1
μ
F
will become
Q.
A parallel plate capacitor with air as dielectric is charged to a potential 'V' using a battery. Removing the battery, the charged capacitor is then connected across an identical uncharged parallel plate capacitor filled with wax of dielectric constant 'K' the common potential of both the capacitor is
Q.
Condenser
A
has a capacity of
15
μ
F
when it is filled with a medium of dielectric constant
15
. Another condenser
B
has a capacity
1
μ
F
with air between the plates. Both are charged separately by a battery of
100
V
. After charging, both are connected in parallel without the battery and the dielectric material being removed. The common potential now is :
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