Question

+2C and +6C two charges are repelling each other with a force of 12 N. If each charge is given -2C of charge, then the value of the force will be

• A. 4 N (Attractive)
• B. 4 N (Repulsive)
• C. 8 N (Repulsive)
• D. Zero

Answer 1

The correct option is D Zero

Resultant charges after adding the -2c be $(-2+2)=0$ and $(-2+6)=+4C\Rightarrow F=\frac{k{Q}_1{Q}_2}{r^2}=k\times \frac{0\times 4}{r^2}=0$