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Stoichiometric Calculations

2K+2H2O→ 2KOH...

Question

$2 K + 2 H_{2} O \to 2 K O H + H_{2}$
If $2.0 m o l e s$ of potassium react with excess water, how many moles of hydrogen gas will be produced?

22.4

mol

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2.0

mol

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1.0

mol

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11.2

mol

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Solution

The correct option is C $1.0$ mol
$2 K + 2 H_{2} O \to 2 K O H + H_{2} ↑$
According to law of conservation of matter, $2 m o l e s$ of potassium react with water to produce $1 m o l e$ of hydrogen gas.
So, $2 m o l e s$ of potassium produce $1 m o l e$ of hydrogen gas.

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