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Question


2mol of A2 gas in one flask (1 lit volume) is allowed to react with 4 mol of B2 gas presence in another flask (3 lit volume) as A2 (g)+B2 (g)2AB (g);Kc=4 at 27oC. What is the concentration of AB when equilibrium is established?

A
1.33 M
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B
2.66 M
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C
0.66 M
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D
0.33 M
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Solution

The correct option is C 0.66 M
The reaction is,

A2(g)+B2(g)2AB(g)Moles at eqm2x4x2x

Kc=4x2(2x)(4x)

putting values, we get;
x=3224=1.33 mole

Here total volume=1l+3l=4l
Concentration of AB=2xvolume
=2x4
Putting the values,
Concentration of AB = 0.66 M

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