2 mol of A 2 gas in one flask 1 lit volume is allowed to react with 4 mol of B 2 gas presence in another flask 3 lit volume as A 2 g - B 2 g - 2 AB g - K c -4 at 27- C- What is the concentration of AB when equilibrium is established- A- 1-33 MB- 2-66 MC- 0-66 MD- 0-33 M

The correct option is C 0.66 M nbsp;The reaction is, [ amp; A_2(g) amp; + amp; B_2(g) amp; ⇌ amp; 2AB(g); Moles at ...

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Standard XII

Chemistry

Derivation of Kp and Kc

2 mol of A 2 ...

Question

2mol of $A_{2}$ gas in one flask (1 lit volume) is allowed to react with 4 mol of $B_{2}$ gas presence in another flask (3 lit volume) as $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4 a t 27^{o} C .$ What is the concentration of AB when equilibrium is established?

1.33 M

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2.66 M

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0.66 M

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0.33 M

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Solution

The correct option is C 0.66 M
The reaction is,

$\begin{matrix} A_{2} (g) & + & B_{2} (g) & ⇌ & 2 A B (g) M o l e s a t e q m & 2 - x & 4 - x & 2 x \end{matrix}$

$K_{c} = \frac{4 x^{2}}{(2 - x) (4 - x)}$

putting values, we get;
$\Rightarrow x = \frac{32}{24} = 1.33 m o l e$

Here total volume= $1 l + 3 l = 4 l$
Concentration of AB= $\frac{2 x}{v o l u m e}$
= $\frac{2 x}{4}$
Putting the values,
Concentration of AB = $0.66 M$

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Similar questions

The gas $A_{2}$ in the left flask allowed to react with gas $B_{2}$ present in right flask as ?

$A_{2} + B_{2} ⇌ 2 A B (g); K_{c} = 4 a t 27^{\circ} C$
What is the concentration of AB when equillibrium is established-

Q.

2mol of

A_{2}

gas in one flask (1 lit volume) is allowed to react with 4 mol of

B_{2}

gas presence in another flask (3 lit volume) as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4 a t 27^{o} C .

What is the concentration of AB when equilibrium is established?

Q. The gas

A_{2}

in the left flask is allowed to react with gas

B_{2}

presence in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4

27^{o} C

. What is the concentration of

A B

when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask at

A_{2} (g) + B_{2} (g) ⇌ 2 A B (g), K_{C} = 4

27^{\circ} C

. What is the concentration of

A B

when equilibrium is established?

Q. The gas

A_{2}

in the left flask allowed to react with gas

B_{2}

present in right flask as

A_{2} (g) + B_{2} (g) ⇌ 2 {AB(g) ; K}_{C} = 4 at 27^{\circ} C

What is the concentration of

A B

when equilibrium is established?

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2mol of A2 gas in one flask (1 lit volume) is allowed to react with 4 mol of B2 gas presence in another flask (3 lit volume) as A2 (g)+B2 (g)⇌2AB (g);Kc=4 at 27oC. What is the concentration of AB when equilibrium is established?

The correct option is C 0.66 M The reaction is, A2(g)+B2(g)⇌2AB(g)Moles at eqm2−x4−x2x Kc=4x2(2−x)(4−x) putting values, we get; ⇒x=3224=1.33 mole Here total volume=1l+3l=4l Concentration of AB=2xvolume =2x4 Putting the values, Concentration of AB = 0.66 M

2mol of $A_{2}$ gas in one flask (1 lit volume) is allowed to react with 4 mol of $B_{2}$ gas presence in another flask (3 lit volume) as $A_{2} (g) + B_{2} (g) ⇌ 2 A B (g); K_{c} = 4 a t 27^{o} C .$ What is the concentration of AB when equilibrium is established?