The correct option is B n = 2, l =1 2p orbitals have nbsp; n = 2, l =1 . ...

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Quantum Numbers

2p orbitals h...

Question

2p orbitals have:

n = 1, l = 2

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n = 1, l = 0

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n = 2, l = 1

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n = 2, l = 0

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Solution

The correct option is B $n = 2, l = 1$
2p orbitals have $n = 2, l = 1$ .

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Similar questions

n = 1, l = 0, m = 0

n = 2, l = 0, m = 0

n = 2, l = 1, m = 1

n = 3, l = 2, m = 1

n = 3, l = 2, m = 0

(1) n = 1, l = 0, m = 0

(2) n = 2, l = 1, m = -1

(3) n = 2, l = 1, m = +1

(4) n = 3, l = 2, m = +1

(5) n = 3, l = 2, m = 0

Let S_{n} = \sum_{l = 1}^{n} (\frac{l^{4} + l^{3} n + l^{2} n^{2} + 2 n^{4}}{n^{5}}) and T_{n} = \sum_{l = 0}^{n - 1} (\frac{l^{4} + l^{3} n + l^{2} n^{2} + 2 n^{4}}{n^{5}}), (n = 1, 2, 3, . . .) then

n = 0

l = 0

m_{1} = 0

m_{s} = + 1 / 2

n = 1

l = 0

m_{1} = 0

m_{s} = - 1 / 2

n = 1

l = 1

m_{1} = 0

m_{s} = + 1 / 2

n = 2

l = 1

m_{1} = 0

m_{s} = - 1 / 2

n = 2

l = 3

m_{1} = - 3

m_{s} = + 1 / 2

n = 3

l = 1

m_{1} = 0

m_{s} = + 1 / 2

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