2 pq -4 pr -3 sq -6 sr -2 p -3 s -A- q -2 r B- q -2 r C- q - r D- q - r

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Factorisation by Grouping Terms

2 pq +4 pr -3...

Question

$2 p q + 4 p r - 3 s q - 6 s r$ = $(2 p - 3 s) \times$

(q + 2 r)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(q - 2 r)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(q + r)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(q - r)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Factorise: p^{2} + q^{2} + 2 (p q + q r + r p) .

\to p, \to q, \to r

\to x

\to p [(\to x - \to q) \times \to p] + \to q \times [(\to x - \to r) \times \to q] + \to r \times [(\to x - \to p) \times \to r] = \to 0

\to x

(p \lor q) \land (q \lor \sim r)

The negation of $q \lor \sim (p \land r)$ is ___.

If S(p,q,r)= $\sim p \lor \sim (q \lor r)$ is a compund statement, then S(~p,~q,~r) is

Join BYJU'S Learning Program