2x2_13x+18
Factoring 2x2-13x+18
The first term is, 2x2 its coefficient is 2 .
The middle term is, -13x its coefficient is -13 .
The last term, "the constant", is +18
Step-1 : Multiply the coefficient of the first term by the constant 2 • 18 = 36
Step-2 : Find two factors of 36 whose sum equals the coefficient of the middle term, which is -13 .
-36 | + | -1 | = | -37 | ||
-18 | + | -2 | = | -20 | ||
-12 | + | -3 | = | -15 | ||
-9 | + | -4 | = | -13 | That's it |
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -9 and -4
2x2 - 9x - 4x - 18
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x-9)
Add up the last 2 terms, pulling out common factors :
2 • (2x-9)
Step-5 : Add up the four terms of step 4 :
(x-2) • (2x-9)
Which is the desired factorization
A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.
Solve : 2x-9 = 0
Add 9 to both sides of the equation :
2x = 9
Divide both sides of the equation by 2:
x = 9/2 = 4.500
Solve : x-2 = 0
Add 2 to both sides of the equation :
x = 2