$2 y^{3} + y^{2} - 2 y - 1 =$ ___________.

(y - 1) (y + 1) (2 y + 1)

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(y + 1) (y + 1) (2 y - 1)

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(2 y - 1) (y + 1) (2 y + 1)

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Solution

The correct option is A $(y - 1) (y + 1) (2 y + 1)$

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Similar questions

2 y^{3} + y^{2} - 2 y - 1

{2 y}^{3} + y^{2} - 2 y - 1

2 y^{3} + y^{2} - 2 y - 1

Factorise :
(i) $x^{3}$ −2 $x^{2}$ −x+2
(ii) 2 $y^{3}$ + $y^{2}$ −2y−1

2 y^{3} + y^{2} - 2 y - 1 = (x + a) (x - b) (c x + d)

a + b + c + d

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