Question

2y² + 5y – 3 = 0

Answer 1

Given: 2y² + 5y – 3 = 0
To find the nature of the roots, we need to find the discriminant of the given quadratic equation.
We know that the discriminant of a quadratic equation, Δ = b² – 4ac.
On comparing the given equation with ay² + by + c = 0, we get:
a = 2, b = 5 and c = –3
Thus,
Δ = (5)² – 4(2)(–3)
$\Rightarrow$Δ = 25 + 24 = 49
Since Δ > 0, the roots of the given quadratic equation are real and unequal.