2y³ + y² − 2y − 1

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Solution

Let be the given polynomial.

Now, putting we get

Now,

Hence are the factors of polynomial f(y).

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Similar questions

2 y^{3} + y^{2} - 2 y - 1

{2 y}^{3} + y^{2} - 2 y - 1

2 y^{3} + y^{2} - 2 y - 1

Factorise :
(i) $x^{3}$ −2 $x^{2}$ −x+2
(ii) 2 $y^{3}$ + $y^{2}$ −2y−1

2 y^{3} + y^{2} - 2 y - 1 = (x + a) (x - b) (c x + d)

a + b + c + d

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