Question

3.6 g of an ideal gas was injected into a bulb of internal volume of 8 L at pressure P atm and temp T K. The bulb was then placed in a thermostat maintained at $(T+15)K$. 0.6 g of the gas was left off to keep the original pressure. Find T(in K) if mol weight of gas is 44.(If the answer is X, then enter the answer as $\frac{X}{15}$) :

Answer 1

$P\times 8=\left(\frac{3.6}{M}\right)\times R\times T$ ....(i)
from eq. (i)/(ii)

$P\times 8=\left(\frac{3.0}{M}\right)\times R\times (T+15)$ ...(ii)

$3.6\times T=3(T+15)$

$=3T+45\Rightarrow T=\frac{45}{0.6}=75K$.

$\Rightarrow P=\frac{3.6}{44}\times \frac{0.0821\times 75}{8}=0.062atm$.