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Ways of Representing the Concentration of a Solution

3.6 grams of ...

Question

3.6 grams of oxalic acid dissolve and volume is made upto 150 ml. Calculate the normatity of the solution for redox titration

7.45

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0.38

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0.25

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1.75

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Solution

The correct option is B $0.38$ N
Oxalic acid on dehydration give $0.057$ mole equavelent.
The solution's normality will be
$N = \frac{no.of moles eq.}{V}$
$N = \frac{0.057 moles eq.}{0.150}$
$= 0.38$

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