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Laws of Definite Proportions, Multiple Proportions

3. A solution...

Question

3. A solution containing 10g per dm3 of Urea is isotonic with 5% of a nonvolatile solute . calculate gram molecular weight of non volatile solute

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Solution

Dear Student,

The computation are expressed below,

$m o l e s o f u r e a = \frac{10 g}{60 \frac{g}{m o l}} = 0.167 m o l c o n c e n t r a t i o n o f u r e a = \frac{0.167 m o l}{1 l t} = 0.167 M b y t a k i n g b a s i s a s 1000 m l 5 % = 50 g m p e r l t m o l e s o f u n k n o w n s o l u t e = \frac{50}{m} m o l c o n c e n t r a t i o n o f u n k n o w n s o l u t i o n = \frac{50}{m} \frac{m o l}{L} n o w b y c o m p u t i n g k n o w n a n d u n k n o w n w e g e t, 0.167 = \frac{50}{m} m = 299.401 \frac{g}{m o l (m o l a r m a s s)}$
Regards.

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