Question

(3) Draw ∆STD, such that m∠T = 80°, l (ST) = 5.8 cm and l (TD) = 6.2 cm.

Answer 1

Steps of construction:

(1) Draw a line segment TD = 6.2 cm.
(2) Placing the protractor at vertex T on segment TD, draw $\angle XTD=80°$.
(3) Taking T as centre, draw an arc of radius 5.8 cm that intersects the ray XT at S.
(4) Join S and D.
The required ∆STD is thus drawn.