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Byju's Answer

Standard XII

Chemistry

Kolbe Electrolysis for Alkenes

3 moles of et...

Question

3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of
bromoethane and 1 mole of (X). Here (X) is:

H_{3} P O_{4}

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H_{3} P O_{2}

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H P O_{3}

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H_{3} P O_{3}

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Solution

The correct option is B $H_{3} P O_{3}$
3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of bromoethane and 1 mole of orthophosphorus acid $(H_{3} P O_{3})$ .
$3 C_{2} H_{5} O H + P B r_{3} \to 3 C_{2} H_{5} B r + H_{3} P O_{3}$

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Similar questions

Q. Assertion :Both

H_{3} P O_{3}

and

H_{3} P O_{4}

have the same number of hydrogen atoms but

H_{3} P O_{4}

is a tribasic acid and

H_{3} P O_{3}

is a dibasic acid Reason: 1 mole of

H_{3} P O_{3}

is neutralised by 2 moles of

N a O H

while 1 mole of

H_{3} P O_{4}

is neutralised by 3 moles of

N a O H

Q. Assertion :When 1 mole of hypophosphorous acid is treated with excess of iodine in acidic solution, 1 mole of iodine is reduced; on making the solution alkaline, another mole of iodine is consumed. Reason:

H_{3} P O_{2} + I_{2} + H_{2} O ⟶ H_{3} P O_{3} + 2 I^{-} + 2 H^{+} H_{3} P O_{3} + I_{2} + 2 O H^{-} ⟶ H_{3} P O_{4} + 2 I^{-} + H_{2} O

Q. If 2 moles of

B a (O H)_{2}

reacts with 21 moles of

H_{3} P O_{4}

then moles of product

B a_{3} (P O_{4})_{2}

formed are

1 mole of how many of the following acids neutralize exactly one mole of NaOH, under required favorable conditions? $H C l, H N O_{3}, H_{2} S O_{4}, H_{2} S O_{3}, H_{3} P O_{4}, H_{3} P O_{3}, H_{3} P O_{2}, H_{4} P_{2} O_{5}, H_{3} B O_{3}$ ___

Q. The order of the oxidation state of the phosphorous atom in

H_{3} P O_{2}, H_{3} P O_{4}, H_{3} P O_{3}

, and

H_{4} P_{2} O_{6}

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3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles ofbromoethane and 1 mole of (X). Here (X) is:

The correct option is B H3PO33 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of bromoethane and 1 mole of orthophosphorus acid (H3PO3).3C2H5OH+PBr3→3C2H5Br+H3PO3

3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of
bromoethane and 1 mole of (X). Here (X) is:

The correct option is B $H_{3} P O_{3}$
3 moles of ethanol reacts with 1 mole of phosphorous tribromide to form 3 moles of bromoethane and 1 mole of orthophosphorus acid $(H_{3} P O_{3})$ .
$3 C_{2} H_{5} O H + P B r_{3} \to 3 C_{2} H_{5} B r + H_{3} P O_{3}$