Question

3%solution of glucose is isotonic with 1% solution of a non-volatile non-electrolyte substance the molecular mass of the substance would be

• A. 30
• B. 60
• C. 90
• D. 120

Answer 1

The correct option is B 60

since the two solution are isotonic,

therefore, $C_{1}RT=C_{2}RT$

$C_1=C_2$

let mass of solution = 100 g

so mass of glucose = 3g

and mass of non-volatile substance = 1g

so, we get

$\frac{3}{180}=\frac{1}{M}$

$M=60$

hence, molecular mass of non-volatile substance = 60