Electrolytic Dissociation
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An aqueous solution of BaCl2 (1.28gm in 100gm of water)boils at 100.0832∘ at 1 atm. Calculate the degree of dissociation. ( Kb of water is 0.512 k/m)
0.5
0.75
0.85
0.6
x moles of an organic non-volatile monobasic acid were taken and dissolved in water. The change in boiling point △Tb. pH of the solution will be
−log10 [x]
−log10 [△TbKb−x]
−log10 [2x]
None of the above
- hydrogen, chlorine
- sodium, hydrogen
- chlorine, sodium
- sodium, chlorine
(given that λ∘NH+4 = 73.4 and λ∘OH− = 197.6 ohm−1cm2mol−1 )
- 0.0424
- 0.0212
- 0.0848
- 0.004
A gaseous compound of molecular mass 82.1 dissociates on heating to 400K as : X2Y4(g)→X2(g)+2Y2(g). The density of the equilibrium mixture at a pressure of 1 atm and temperature of 400K is 2.0g L−1. The compound dissociates to the extent of :
95.1%
47.6%
12.5%
None of these
C = 0.2 M
When 0.004MNa2SO4 is isotonic with 0.01M solution of glucose at same temperature.the apparent degree of dissociation of sodium sulphate is
75%
50%
25%
85%
Oxygen bubbles will be formed at the electrode which is connected to the negative terminal of the battery
Hydrogen gas will be formed at the electrode which is connected to the positive terminal of the battery
No gas is formed at any electrode
Hydrogen gas will be formed at the electrode which is connected to the negative terminal of the battery
- 2H3O+ (aq)+4e−→H2 (g)+2O2(g)
- H2SO4 (l)+H2O (l)→2H3O+(aq)+SO2−4
- 2H2O (l)→O2 (g)+4H+ (aq)+4e−
- 2H3O+ (aq)+2e−→H2 (g)+2H2O (l)
- lead
- bromine
- hydrogen
- oxygen