Question

$3\text{g}$ of an oxide of a metal is converted to form $5\text{g}$ of its chloride. The equivalent weight of the metal is:

• A. $33.25\text{g}$
• B. $45.63\text{g}$
• C. $63.57\text{g}$
• D. $98.81\text{g}$

Answer 1

The correct option is A $33.25\text{g}$

Let the equivalent weight of the metal be $M$
weight of the metal oxide = $3\text{g}$
weight of the metal chloride = $5\text{g}$

$\frac{\text{weight of the metal chloride}}{\text{weight of the metal oxide}}=\frac{\text{equivalent weight of the metal chloride}}{\text{equivalent weight of the metal oxide}}$

$\Rightarrow \frac{5}{3}=\frac{M+35.5}{M+8}$
On solving, $M=33.25\text{g}$