300 litres of ammonia gas at $20^{0} C$ and 20 atmosphere pressure are allowed to expand in a space of 600 litres capacity and to a pressure of one atmosphere .Calculate the drop in temperature.

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Solution

Here,

$\frac{P V}{T} = c o n s t a n t$

$∴ \frac{20 \times 300}{293} = \frac{1 \times 600}{T}$

$∴ T = 29.3$ $K$

Drop in temperature $= 293 - 29.3 = 263.7$ $K$ or ${263.7}^{o} C$

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300 litres of ammonia gas at 200C and 20 atmosphere pressure are allowed to expand in a space of 600 litres capacity and to a pressure of one atmosphere .Calculate the drop in temperature.

Here, PVT=constant ∴20×300293=1×600T ∴T=29.3 K Drop in temperature =293−29.3=263.7 K or 263.7oC

300 litres of ammonia gas at $20^{0} C$ and 20 atmosphere pressure are allowed to expand in a space of 600 litres capacity and to a pressure of one atmosphere .Calculate the drop in temperature.

Here,

$\frac{P V}{T} = c o n s t a n t$

$∴ \frac{20 \times 300}{293} = \frac{1 \times 600}{T}$

$∴ T = 29.3$ $K$

Drop in temperature $= 293 - 29.3 = 263.7$ $K$ or ${263.7}^{o} C$