$34 + 32 + 30 + \dots + 10$ =

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Solution

$34 + 32 + 30 + . . . . . . + 10 L e t n u m b e r o f t e r m o f t h i s A P b e n, t h e n 10 = 34 + (n - 1) (- 2) 10 = 34 - 2 n + 2 2 n = 26 ∴ n = 13$
$∴ S u m = (\frac{13}{2}) [2 \cdot 34 + (13 - 1) (- 2)] = (\frac{13}{2}) (68 - 24) = 286$

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