34.A bar of iron is 10 cmat 20'C.At 19'C it will be (alpha Fe=11×10-6/^° C) 1) 11×10-6 cm longer 2)11×10-6 cm shorter 3)11×10-5 cm shorter 4)11×10-5 cm longer

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A bar of iron is 10 cm at $20^{o} C$ . At $19^{o} C$ it will be (a of iron = 11 X $10^{- 6} /^{o} C$ )

A bar of iron is 10 cm at 20°C. At 19°C it will be (a of iron = 11 x 10^-6/°C)

A bar of iron is 10 cm at 20°C. At 19°C it will be (a of iron = 11 ´ 10^-6/°C)

10 c m

20^{o}

19^{o}

α_{F e}

10^{- 6} /^{o} C

A bar of iron is 10 cm at 20°C. At 19°C it will be (a of iron = 11 x 10^-6/°C)

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