$(35)^{2} - (28)^{2} = m^{2}$ . What is the value of $m$ ?

7

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21

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49

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14

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Solution

The correct option is B $21$
${(35)}^{2} - {(28)}^{2} = m^{2} 35^{2} - 28^{2} = (35 + 28) (35 - 28) ∵ [a^{2} - b^{2} = (a + b) (a - b)] = 63 \times 7 = 441 ∴ m^{2} = 441 \Rightarrow m = \sqrt{441} = 21$

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\frac{7^{- 5} \times 49 \times 21}{14^{2} \times 7^{- 3}}

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Class	$0 - 7$	$7 - 14$	$14 - 21$	$21 - 28$	$28 - 35$	$35 - 42$	$42 - 49$	$49 - 56$
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\frac{7}{11} \times \frac{33}{49} \times \frac{14}{44} + \frac{19}{22} = ?

- 2 (1 - m^{2}) - 4

(m^{2} - (2 - m^{2}))

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