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Implicit Differentiation

35. If b tan ...

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35. If b tan theta=a ,then the value of a sin theta-b cos theta/a sin theta+b cos theta is

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b tan θ = a

, then the value of

\frac{a sin θ - b cos θ}{a sin θ + b cos θ}

\tan θ = \frac{a}{b}

, find the value of

\frac{\cos θ + \sin θ}{\cos θ - \sin θ}

tan θ = \frac{a}{b}

\frac{a sin θ - b cos θ}{a sin θ + b cos θ} = . . . . .

5 \tan θ = 3 then (\frac{5 \sin θ - \cos θ}{5 \sin θ + \cos θ}) = ?

\frac{2}{3}

\frac{1}{3}

\frac{1}{2}

\frac{3}{5}

a^{2} (1 - sin θ) + b^{2} (1 + sin θ) = 2 a b cos θ

, then the value of

tan θ

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