The correct option is B 35 × 7 +100 35 × 107 = 35 × (100 +7) = ( 35) × 100 + ( 35) × 7 [using distributive property, i.e.,a × (b + c) = a × b + a × c] = ...

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Introduction to Integers

-35 × 107=

Question

$- 35 \times 107 \neq$ ______

$- 35 \times (100 + 7)$

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$(- 35) \times 7 + (- 35) \times 100$

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$- 35 \times 7 + 100$

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$(- 30 - 5) \times 107$

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Solution

The correct option is C
$- 35 \times 7 + 100$

$- 35 \times 107$

$= - 35 \times (100 + 7)$

$= (- 35) \times 100 + (- 35) \times 7$
[using distributive property, i.e., $a \times (b + c) = a \times b + a \times c]$

$= (- 35) \times 7 + (- 35) \times 100$
[as addition is commutative, i.e., a + b = b + a]

Hence, $- 35 \times 107 \neq$ $- 35 \times 7 + 100$ .

Also, $- 35 \times 107 = (- 30 - 5) \times 107$

$[∵ (- 30 - 5) = (- 35)]$

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Similar questions

Question 18

$- 35 \times 107$ is not same as

(a) $- 35 \times (100 + 7)$
(b) $(- 35) \times 7 + (- 35) \times 100$
(c) $- 35 \times 7 + 100$
(d) $(- 30 - 5) \times 107$

Q. Evaluate:
(i)

\frac{- 3}{5} \times \frac{10}{7}

(ii)

{(\frac{- 5}{8})}^{- 1}

(iii)

{(- 6)}^{- 1}

Q. Simplify:

(1)

\frac{5}{9} + \frac{8}{9}

(2)

\frac{13}{8} - \frac{7}{8}

(3)

\frac{4}{5} + \frac{- 7}{10}

(4)

\frac{- 10}{7} - \frac{1}{2}

(5)

\frac{- 13}{4} + \frac{- 3}{4}

(6)

\frac{- 13}{4} - \frac{- 3}{4}

(7)

\frac{2}{5} - \frac{7}{9}

(8)

\frac{- 3}{5} + \frac{2}{7}

107 \times 107 + 93 \times 93 =

(107 + 2) \times (107 - 2)

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−35×107≠ ______

$- 35 \times 107 \neq$ ______