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Question

3A+2BA3B2
A3B2+2CA3B2C2
The above two reactions are carried out by taking 2 mol of each of B and C and 3 mol of A. Then which option(s) is/are correct?

A
1 mol of A3B2C2 is formed
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B
Half mol of A3B2C2 is formed
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C
Half mol of A3B2 is formed in first reaction
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D
1 mol of A3B2 is formed in first reaction
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Solution

The correct options are
A 1 mol of A3B2C2 is formed
D 1 mol of A3B2 is formed in first reaction
3A+2BA3B2(balanced)
A3B2+2CA3B2C2(balanced)

Now, 3 mol of A reacts with 2 mol of B to form 1 mol of A3B2.
So, 1 mol of A3B2 is formed when 3 mol of A and 2 mol of B are taken.
2 mol of C reacts with 1 mol of A3B2 to give 1 mol of A3B2C2.
Therefore, correct options are (a) and (d).

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