The correct options are
A 1 mol of A3B2C2 is formed
D 1 mol of A3B2 is formed in first reaction
3A+2B→A3B2(balanced)
A3B2+2C→A3B2C2(balanced)
Now, 3 mol of A reacts with 2 mol of B to form 1 mol of A3B2.
So, 1 mol of A3B2 is formed when 3 mol of A and 2 mol of B are taken.
2 mol of C reacts with 1 mol of A3B2 to give 1 mol of A3B2C2.
Therefore, correct options are (a) and (d).