3a9 is divisible by 9 if the digit 'a' is equal to
6
For the number to be divisible by 9 the sum of digits of number must be divisible by 9.
Sum of the digits of 3a9 = 3 + a + 9 = 12 + a
12 + a should be a multiple of 9 to satisfy the condition. The nearest multiple of 9 next to 12 is 18.
Therefore, 12 + a = 18
So, a = 18 - 12 = 6