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Question

Find the smallest value of 'a' if 3a9 is divisible by 9.


A

2

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B

4

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C

6

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D

8

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Solution

The correct option is C

6


For a number to be divisible by 9, sum of the digits of the number must be a multiple of 9.

Sum of the digits of 3a9
= 3 + a + 9
= 12 + a

12 + a should be a multiple of 9 to satisfy the condition. The smallest multiple of 9 greater than 12 is 18.

Therefore, 12 + a = 18
a = 18 - 12 = 6

Therefore, the smallest value of a which will make 3a9 divisible by 9 is 6.


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