Question

$3Cu+8HN{O}_3\to 3Cu(N{O}_3{)}_2+2NO+4H_{2}O$
Which of the following statements are wrong for the above reaction?

• A. $Cu$ is oxidized
• B. $HN{O}_3$ is reduced
• C. $Cu$ is reduced
• D. $Cu$ acts as reducting agent

Answer 1

Answer: (B), (D)

$HN{O}_3$ is reduced
$Cu$ acts as reducting agent

In the reaction,
$3Cu+8HN{O}_3\to 3Cu(N{O}_3{)}_2+2NO+4H_{2}O$, copper atom loses two electrons to form $Cu\left(II\right)$ ion. In this process, it changes its oxidation state from $0$ to $+2$. Thus, copper is oxidized. During the reaction, nitrogen present in nitric acid changes its oxidation state from $+5$ to $+2$. Thus, it is reduced.
Hence, copper acts as reducing agent.