$3 F e + 4 H_{2} O ⟶ F e_{3} O_{4} + 4 H_{2}$
If the atomic mass of iron is 56, then its equivalent mass will be :

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Solution

The correct option is A 21
$3 F e + 4 H_{2} O ⟶ F e_{3} O_{4} + 4 H_{2}$
0 $\frac{8}{3}$
So, Equivalent weight of Fe $= \frac{56}{\frac{8}{3}} = 21$

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