$3 H N O_{2} ⟶ 2 N O + H N O_{3} + H_{2} O$
This is a disproportionation reaction.
If true enter 1, else enter 0.

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Solution

Disproportionation is a specific type of redox reaction in which a species is simultaneously reduced and oxidised to form two different products.
$3 H N O_{2} ⟶ 2 N O + H N O_{3} + H_{2} O$
$H N O_{2}$ is simultaneously reduced and oxidised to form $N O$ and $H N O_{3}$ .
So, above reaction is disproportion reaction.
Hence, the statement is correct.

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